Question

A cannonball is launched from level ground at an angle of elevation of 55 degrees and observe to impact level ground downrange at a distance of 432 m. The same cannon is then used to launch a cannonball from level ground at an angle of elevation of 38 degrees into the side of a cliff and the cannonball is observed to strike the cliff 28.5 m above level ground.

A) How far is the base of the cliff from the cannon (measured along level ground)?

B) What maximum height does the cannonball reack above level ground?

C) What is the impact velocity of the cannonball with the cliff? (state your answer in i-j notation.)

Answer #1

**Let vo is the initial velocity of the canon
ball.**

**R = vo^2*sin(2*theta)/g**

**vo = sqrt(R*g/sin(2*theta))**

**= sqrt(432*9.8/sin(2*55))**

**= 67.1 m/s**

**A) when projected at 38 degrees.**

**vox = vo*cos(38) = 67.1*cos(38) = 52.88 m/s**

**voy = vo*sin(38) = 67.1*sin(38) = 41.31 m/s**

**let t is the time taken to hit th cliff.**

**h = voy*t - 0.5*g*t^2**

**28.5 = 41.31*t - 4.9*t^2**

**4.9*t^2 - 41.31*t + 28.5 = 0**

**on solving the above eqiation we get**

**t = 7.67 s**

**so, x = vox*t**

**= 52.88*7.67**

**= 405.6 m
<<<<<<----------Answrr**

**b) Hmax = voy^2/(2*g)**

**= 41.31^2/(2*9.8)**

**= 87 m
<<<<<<----------Answrr**

**c) vy = voy - g*t**

**= 41.31 - 9.8*7.67**

**= -33.8 m/s**

**so, v = vx i + vy j**

**= (52.88 i - 33.8 j )m/s
<<<<<<----------Answrr**

A
con on at ground level launches a cannonball horizontally. If the
cannon fires with a velocity of 28.3m/s and at an angle of 30
degrees how far will the cannonball travel?

A cannonball is shot (from ground level) with an initial
horizontal velocity of 33 m/s and an initial vertical velocity of
25 m/s.
What is the initial speed of the cannonball?
What is the initial angle θ of the cannonball with respect to
the ground?
What is the maximum height the cannonball goes above the
ground?
How far from where it was shot will the cannonball land?
What is the speed of the cannonball 3.6 seconds after it was
shot?...

A cannonball is fired with an initial velocity of 100 m/s at an
angle of 35 degrees above the positive x-axis.
The target is the enemy King's tower.
The cannon is positioned 300 m from the base of the King's
tower, on a flat, horizontal field. The cannonball takes 3.66 s to
strike the tower after it is fired.
1. At what height on the tower does the cannonball strike?
2. What is the approximate magnitude of the cannonball's
velocity...

a ball is launched at an upward angle of 39.6 degrees from the
horizontal at 40.2 m/s from the ground. if it lands on a cliff that
is 7.5 m high, how long is the ball in the air?

For an object being launched at ground level at a tilted
non-zero initial velocity, is the velocity zero anywhere? Are the
horizontal or vertical components of the velocity zero at any
point?
What is the shape of this trajectory? (Use the mathematical
term).
If an object is launched with a strictly horizontal initial
velocity, what is the vertical component of the initial
velocity?
Will an object take longer, less, or the same amount of time to
reach the ground if...

A projectile is launched from a cannon; it has an initial speed
of 85 m/s at an angle of 33 degrees above horizontal. The muzzle of
the cannon is 2.5 meters above the ground. How far down range will
the projectile land?

A
projectile is launched from ground level at 55 m/s at a 35 degree
angle. Air resistance is negligible.
a) What is the maximum height reached by the projectile?
b) What is the velocity (magnitude and direction) of the
projectile at t=2.0 s?
c) A target with an adjustable height is placed 215 m away
from where the projectile is launched. How high should the target
be adjusted so that the projectile hits the top of the target on
its...

King Arthur's knights fire a cannon from the top of the castle
wall. The cannonball is fired at a speed of 58 m/s and an angle of
45°. A cannonball that was accidentally dropped hits the
moat below in 1.97 s.
How far from the castle wall does the cannonball hit the
ground?
What is the ball's maximum height above the ground?

King Arthur's knights fire a cannon from the top of the castle
wall. The cannonball is fired at a speed of 40 m/s and at an angle
of 35°. A cannonball that was accidentally dropped hits the moat
below in 1.2 s.
(a) How far from the castle wall does the cannonball hit the
ground?
(b) What is the ball's maximum height above the ground?

King Arthur's knights fire a cannon from the top of the castle
wall. The cannonball is fired at a speed of 60 m/s and at an angle
of 27°. A cannonball that was accidentally dropped hits the moat
below in 1.0 s. (a) How far from the castle wall does the
cannonball hit the ground? Incorrect: Your answer is incorrect. m
(b) What is the ball's maximum height above the ground? m

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 23 minutes ago

asked 24 minutes ago

asked 40 minutes ago

asked 45 minutes ago

asked 45 minutes ago

asked 45 minutes ago

asked 48 minutes ago

asked 49 minutes ago

asked 56 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago