Question

A simple pendulum on the surface of Earth is found to undergo 14.0 complete small-amplitude oscillations...

A simple pendulum on the surface of Earth is found to undergo 14.0 complete small-amplitude oscillations in 7.65 s. Find the pendulum's length.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
17 a). A simple pendulum on the surface of Earth is found to undergo 12.0 complete...
17 a). A simple pendulum on the surface of Earth is found to undergo 12.0 complete small-amplitude oscillations in 7.35 s. Find the pendulum\'s length. 17 b): A 126-kg sculpture hangs from a horizontal rod that serves as a pivot about which the sculpture can oscillate. The sculpture\'s moment of inertia with respect to the pivot is 11.3 kg·m2, and when it is swung at small amplitudes, it is found to oscillate at a frequency of 0.539 Hz. How far...
A simple pendulum makes 116 complete oscillations in 2.90 min at a location where g =...
A simple pendulum makes 116 complete oscillations in 2.90 min at a location where g = 9.80 m/s2. (a) Find the period of the pendulum. s (b) Find the length of the pendulum. m
8. A simple pendulum of length 2m makes 100 complete oscillations (cycles) in 204 seconds at...
8. A simple pendulum of length 2m makes 100 complete oscillations (cycles) in 204 seconds at a certain location (not necessarily Earth). a) What is the period for the pendulum? b.) What is the acceleration of gravity (g) at this location? c) What is the angular frequency (w)?
Pendulum A located on the earth and pendulum B located on another planet have the same...
Pendulum A located on the earth and pendulum B located on another planet have the same period for small angle oscillations. What is the ratio of the length of pendulum A to the length of pendulum B? The acceleration due to the gravity on the surface of the planet is 1.6m/s2.
57). (Formulation of Differential Equation Models): Consider the problem of a simple pendulum with a mass...
57). (Formulation of Differential Equation Models): Consider the problem of a simple pendulum with a mass m and string length L. Formulate the differential equation along with initial condition that describes the oscillations of the pendulum with and without damping (or air resistance) and also for small as well as large amplitude oscillations. PS: please try to express the meaning of each of the terms in your equation
A simple pendulum of length L and mass m is suspended in a car traveling with...
A simple pendulum of length L and mass m is suspended in a car traveling with angular velocity (w) around a circle of radius R. Find the equilibrium angle as a function of w and the frequency of small oscillations around the equilibrium point(s).
The period T of a simple pendulum is the amount of time required for it to...
The period T of a simple pendulum is the amount of time required for it to undergo one complete oscillation. If the length of the pendulum is L and the acceleration of gravity is g, then T is given by T=2πLpgq Find the powers p and q required for dimensional consistency. Enter your answers numerically separated by a comma.
Simple Pendulum with Gravity A pendulum consists of a mass m = 0.08 kg hanging from...
Simple Pendulum with Gravity A pendulum consists of a mass m = 0.08 kg hanging from a flexible string of length L. The string is very thin, very light, and does not stretch. It makes small oscillations, with a period of 0.622 s. What is the oscillation frequency of the pendulum? Neglect any air resistance. What would the period of the pendulum be on the moon's surface? Indicate for each of the following statements whether it is correct or incorrect....
How much is the period of 1.00 m pendulum on the Moon (g = 1.6 m/s^2)....
How much is the period of 1.00 m pendulum on the Moon (g = 1.6 m/s^2). Answer should be in seconds. On a planet X pendukum of the length .500 m makes 50.0 oscillations in 1.00 minutes. What is the acceleration of gravity on this planet X? WHat is the period of small oscillations of a meter stick suspended by its end near Earths surface (assume g = 9.8 m/s^2). Notice that this is not a simple pendulum but a...
Luke Skywalker (yes, one of the good guys!) has measured the period of a small angle...
Luke Skywalker (yes, one of the good guys!) has measured the period of a small angle pendulum on Earth and found that it is 0.650 s. a) What is the length of this pendulum? cm b) Luke takes this pendulum such that it is a distance 500km above the surface of the Earth. What will the period of the pendulum be here? s c) If Luke takes this pendulum to the surface of the planet Hoth where the acceleration of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT