Question

Which of the following correctly describes the steps to find the acceleration of the given non-linear motion data in Part 2(b) of the lab, using Method 2?

	a.	Reading the equation of the trendline for the graph: y = x2 (the other two numbers are very small and can be ignored) Here, the coefficient of x2 equals (1/2) a Therefore, a = (2)(coefficient of x2) Substituting values we get: a = (2)(0.013) a = 0.026 m/s2
	b.	Reading the equation of the trendline for the graph: y = x2 (the other two numbers are very small and can be ignored) Here, the coefficient of x2 equals (1/2) a Therefore, a = (2)(coefficient of x2) Substituting values we get: a = (2)(1) a = 2 m/s2
	c.	Reading the equation of the trendline for the graph: y = x2 (the other two numbers are very small and can be ignored) Here, the coefficient of x2 equals (1/2) a Therefore, a = (2)(coefficient of x2) Substituting values we get: a = (2)(0.0536) a = 0.11 m/s2
	d.	Reading the equation of the trendline for the graph: y = x2 (the other two numbers are very small and can be ignored) Here, the coefficient of x2 equals (1/2) a Therefore, a = (2)(coefficient of x2) Substituting values we get: a = (2)(1.6328) a = 3.3 m/s2

QUESTION 6

1. Which of the following correctly describes the steps to calculate the acceleration of the given non-linear motion data in Part 2(b) of the lab, using Method 1?

   	a.	Use the kinematic equation for uniformly accelerated motion: x = ½ at2 Rearrange this to solve for acceleration (a): a = ½ x/t2 Substitute values form the data table (any set of values can be used): a = ½ (1)/12 a = 0.5 m/s2
   	b.	Use the kinematic equation for uniformly accelerated motion: x = ½ at2 Rearrange this to solve for acceleration (a): a = sq. root (2xt2) Substitute values form the data table (any set of values can be used): a = sq.root (2)(1)12 a = 1.41m/s2
   	c.	Use the kinematic equation for uniformly accelerated motion: x = ½ at2 Rearrange this to solve for acceleration (a): a = 2x/t2 Substitute values form the data table (any set of values can be used): a = (2)(1)/12 a = 2 m/s2
   	d.	Use the kinematic equation for uniformly accelerated motion: x = ½ at2 Rearrange this to solve for acceleration (a): a = 4xt Substitute values form the data table (any set of values can be used): a = (4)(1)(1) a = 4 m/s2

Answer 1

Since you have not mentioned the original question in which method 1 and method 2 is given. So i answered your question using options.

The answer of first question is option (b) because we have to compare with original equation and after comparision we get a=2(1)=2

The answer of second question is option(a) or option (c) since you not mentioned clearly what is method 1 and method 2.

Although it is a incomplete Question but by using option we can get answer .so i try to answer this question.