Three moles of an ideal gas are expanded adiabatically. During this process, the temperature of the gas decreases from T= 600K to T= 400K. Find the change in internal energy of gas.
Moles of ideal gass n = 3
Specific heat ratio for ideal gas = 1.66
Ideal gas constant R = 8.314 J K−1 mol−1
T1 = 600 K, T2 = 400 K
In adiabatic expansion workdone is W = - nR (T1 -T2)/ ( - 1)
W = - 3x8.314(600 - 400)/ (1.66 - 1) = - 7558.182 J
The workdone in adiabatic expansion (-W) = change in internal energy (dU)
dU = 7558.182 J
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