Question

(a) Your pendulum clock which advances 1.0 s for every complete oscillation of the pendulum is running perfectly on Earth at a site where the magnitude of the acceleration due to gravity is 9.80 m/s2. You send the clock to a location on the Moon where the magnitude of the acceleration due to gravity is 1.65 m/s2. Does the clock run fast or slow on the Moon?

(b) If the clock is started at 12:00 noon, what will it read after a time of 20.6 h has elapsed on Earth? Enter the time to the nearest minute.

Answer #1

Answer:

We know that time period of simple pendulum depends upon only two things 1) Length of string of pendulum 2) Acceleration due gravity

It is given by relationship T = 2π √ L/g

Since, length is fixed, but acceleration due to gravity is different , So Time period will be more on moon. So clock will be slow.

A pendulum clock that works perfectly on Earth is taken to the
Moon. Assume that the free-fall acceleration on the Moon is 1.63
m/s2.
(a) Does it run fast or slow there?
fastslow Neither, it runs the same as on
Earth.
(b) If the clock is started at 12:00 midnight, what will it read
after 17.6 h? (Enter the time to the nearest minute.)
: AM

A pendulum clock that works perfectly on Earth is taken to the
Moon. Assume that the free-fall acceleration on the Moon is 1.63
m/s2.
(b) If the clock is started at 12:00 midnight, what will it read
after 21.0 h? (Enter the time to the nearest minute.)
____ : ___ AM

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