Question

As light moves from air (n 1.00) to amber, it deviates 18 degrees from its 45 degrees angle of incidence. What is the speed of light in amber?

Answer 1

Solution:

Using the given information,

Angle of refraction, = Angle of incidence - deviation = 45^o - 18^o = 27^o

Using snell's law for refractive index of amber

n_airSin_air = n_amberSin_amber

1*SIn45^o = nSin27^o

n = 1.56

Now , Find the speed,

v = c/n where c = 3*10⁸ m/s. speed of light

v = 3*10⁸/1.56

= 1.93*10⁸ m/s.

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