Question

1. Find the resultant electric field at the origin, due to Q1 and Q2. origin =...

1. Find the resultant electric field at the origin, due to Q1 and Q2.

origin = (0,0)

Q1= -70 nC @ (-3m,0m)

Q2= 50 nC @ (4m,-6m)

2. Add a third charge Q3= 25nC @ (2m,8m). Resolve with all 3 charges.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A point charge q1=4.20 nC is fixed at the origin. A second point charge q2=−7.80 nC...
A point charge q1=4.20 nC is fixed at the origin. A second point charge q2=−7.80 nC is fixed at the point x=15.0 cm. (a) Find the point on the +x axis where the electric potential is zero. (b) A third charge, q3=−2.30 nC is then placed at the point x=20.0 cm. Find the net force acting on charge q2 due to the other two charges.
find the electric force vector (x and y component) on a charge of Q4=-1 microcoulombs located...
find the electric force vector (x and y component) on a charge of Q4=-1 microcoulombs located at the origin due to the presence of Q1= 2.7 microcoulombs AT (2,4m) Q2= 2 microcoloumbs at (-2m, 0) and Q3= 2.2 microcoulombs at (0, -4m) (Apologize about the confusion it was microcoulomb not micrometers)
Charge q1 = 5.5 nC is located at the coordinate system origin, while charge q2 =...
Charge q1 = 5.5 nC is located at the coordinate system origin, while charge q2 = -4.61 nC is located at (a, 0), where a = 0.55 m. The point P has coordinates (a, b), where b = 0.25 m. A third charge q3 = 19 nC will be placed later. a) Find the electric potential VP at point P, in volts. Assume the potential is zero at infinity. b) How much work W, in joules, would you have to...
GOAL Use the superposition principle to calculate the electric field due to two point charges. Consider...
GOAL Use the superposition principle to calculate the electric field due to two point charges. Consider the following figure. The resultant electric field  at P equals the vector sum 1 + 2, where 1 is the field due to the positive charge q1and 2 is the field due to the negative charge q2.Two point charges lie along the x-axis in the x y-coordinate plane. Positive charge q1 is at the origin, and negative charge q2 is at (0.300 m, 0). Point...
A point charge q1 = 3.90 nC is placed at the origin, and a second point...
A point charge q1 = 3.90 nC is placed at the origin, and a second point charge q2 = -2.90 nC is placed on the x-axis at x=+ 21.0 cm. A third point charge q3 = 2.00 nC is to be placed on the x-axis between q1 and q2. (Take as zero the potential energy of the three charges when they are infinitely far apart.) a- What is the potential energy of the system of the three charges if q3...
A point charge q1 = 3.90 nC is placed at the origin, and a second point...
A point charge q1 = 3.90 nC is placed at the origin, and a second point charge q2 = -3.10 nC is placed on the x-axis at x=+ 20.0 cm . A third point charge q3 = 2.10 nC is to be placed on the x-axis between q1 and q2. (Take as zero the potential energy of the three charges when they are infinitely far apart.) PART A: What is the potential energy of the system of the three charges...
A point charge q2 = - 7.00 nC is located at the origin and charge q1...
A point charge q2 = - 7.00 nC is located at the origin and charge q1 = 5.00 nC is on the x-axis, 40.0 cm from the origin. a) Find the magnitude and direction of electric field at point P, which has coordinates (40.0 cm,-50.0 cm). b) Find the force on a charge of 5.00 µC placed at point P.
A point charge q2 = - 7.00 nC is located at the origin and charge q1...
A point charge q2 = - 7.00 nC is located at the origin and charge q1 = 5.00 nC is on the x-axis, 40.0 cm from the origin. a) Find the magnitude and direction of electric field at point P, which has coordinates (40.0 cm,-50.0 cm). b) Find the force on a charge of 5.00 µC placed at point P.
A point charge q1 = 4.10 nC is placed at the origin, and a second point...
A point charge q1 = 4.10 nC is placed at the origin, and a second point charge q2 = -3.10 nC is placed on the x-axis at x=+ 21.0 cm . A third point charge q3 = 1.90 nC is to be placed on the x-axis between q1 and q2. (Take as zero the potential energy of the three charges when they are infinitely far apart.) Part A What is the potential energy of the system of the three charges...
three charges are aligned on the x axis. Q1 (-.500micro c) is at the origin. q2...
three charges are aligned on the x axis. Q1 (-.500micro c) is at the origin. q2 (-1.00micro coulomb) is at 30nm to the left of the origin. Q3(+4 micro Coulomb) is at 15. nm to the right of the origin. find total electric force acting on charge at origin.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT