Question

1. During a solar eclipse, the Moon, Earth, and Sun all lie on the same line,...

1. During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.

(a) What force is exerted by the Sun on the Moon?
_____ N

(b) What force is exerted by the Earth on the Moon?
_____N

(c) What force is exerted by the Sun on the Earth?
_____N

2. An artificial satellite circles the Earth in a circular orbit at a location where the acceleration due to gravity is 5.29 m/s2. Determine the orbital period of the satellite.

_____min

Homework Answers

Answer #1

We have

Earth to Sun distance = (1.496x1011m)

Earth to Moon distance = (3.84x108m)

Moon to Sun distance = 1.496x1011m - 3.84x108m = (1.49216x1011m)

Mass of Earth = (5.98x1024kg)

Mass of Moon = (7.36x1022kg)

Mass of Sun = (1.991x1030kg)

G = Universal Gravitational Constant = (6.673x10-11N-m2/kg2)

Solution :-

(a)

FSonM = GMsMm/r2

FSonM = (6.673x10-11N-m2/kg2)(1.991x1030kg)(7.36x1022kg) / (1.49216x1011m)2

FSonM = 43.91768219x1019 N

FSonM = 4.39x1020 Newtons (Toward the Sun)

(b)

FEonM = GMsMm/r2

FEonM = (6.673x10-11N-m2/kg2) (5.98x1024kg)(7.36x1022kg)/(3.84x108m)2

FEonM = 19.917630649x1019 N

FEonM = 1.99x1020 Newtons (Toward the Earth)

(c)

FSonE = GMsMm/r2

FSonE = (6.673x10-11N-m2/kg2)(5.98x1024kg)(1.991x1030kg) / 1.496x1011m)2

FSonE = 35.50016583x1021 N

FSonE = 3.55x1022 Newtons (Toward the Sun)

2)

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