Question

Which of the following capacitors have the smallest charge? Select a parallel plate capacitor with an...

Which of the following capacitors have the smallest charge?

Select a parallel plate capacitor with an area of 10 cm2 and a plate separation of 2 mm connected to a 10-V battery as your answer

a parallel plate capacitor with an area of 10 cm2 and a plate separation of 2 mm connected to a 10-V battery

Select a parallel plate capacitor with an area of 5 cm2 and a plate separation of 1 mm connected to a 10-V battery as your answer

a parallel plate capacitor with an area of 5 cm2 and a plate separation of 1 mm connected to a 10-V battery

Select a parallel plate capacitor with an area of 10 cm2 and a plate separation of 4 mm connected to a 5-V battery as your answer

a parallel plate capacitor with an area of 10 cm2 and a plate separation of 4 mm connected to a 5-V battery

Select A parallel plate capacitor with an area of 20 cm2 and a plate separation of 2 mm connected to a 20-V battery as your answer

A parallel plate capacitor with an area of 20 cm2 and a plate separation of 2 mm connected to a 20-V battery

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Two parallel-plate capacitors C1 and C2 are connected in series to a battery. Both capacitors have...
Two parallel-plate capacitors C1 and C2 are connected in series to a battery. Both capacitors have the same plate area of 3.40 cm2 and plate separation of 2.65 mm. However, the first capacitor C1 is filled with air, while the second capacitor C2 is filled with a dielectric that has a dielectric constant of 3.40. The total charge on the series arrangement is 13.8 pC. (a) What is the battery voltage? V (b) What is the potential difference across each...
A parallel-plate air capacitor of area A= 14.0 cm2 and plate separation d= 2.20 mm is...
A parallel-plate air capacitor of area A= 14.0 cm2 and plate separation d= 2.20 mm is charged by a battery to a voltage 56.0 V. If a dielectric material with κ = 4.00 is inserted so that it fills the volume between the plates (with the capacitor still connected to the battery), how much additional charge will flow from the battery onto the positive plate?
A parallel plate capacitor with a plate area of 23.0 cm2 and air in the space...
A parallel plate capacitor with a plate area of 23.0 cm2 and air in the space between the plates, which are separated by 1.1 mm, is connected to a 12.0-V battery. If the plates are pulled back so that the separation increases to 5.9 mm, how much work is done?
A parallel plate capacitor of area A = 30 cm2 and separation d = 5 mm...
A parallel plate capacitor of area A = 30 cm2 and separation d = 5 mm is charged by a battery of 60-V If the air between the plates is replaced by a dielectric of k= 4, but the battery disconnected before the dielectric inserted, 1) Find the capacitance of the capacitor. 2) What is the charge on the capacitor? 3) What is the energy stored in the capacitor? please explain. Thank you
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor...
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor is then disconnected and the separation between the plates is halved in such a way that so charge leaks off As the plate separation is being halved which of the following parameters remains constant? An air filled k=1 ideal parallel plate capacitor has a capacitance of C. If the area of the plates is doubled insert a dielectric material k=2 and the distance between...
A parallel plate capacitor with a plate area of 20.0 cm2 and plate separation of 8.00...
A parallel plate capacitor with a plate area of 20.0 cm2 and plate separation of 8.00 mm is connected to a constant potential difference of 5.00 V. A dielectric with a dielectric constant of 4.00 is inserted between the plates. a) What is the energy stored in the capacitor? b) The capacitor is disconnected from the battery and the dielectric is removed from the interior of the capacitor. What is the new energy of the capacitor now? c) What does...
A Parallel plate capacitor is charged fully using a 48 V battery such that the charge...
A Parallel plate capacitor is charged fully using a 48 V battery such that the charge on it is 230 pC and the plate separation is 3 mm. The capacitor is then disconnected from the battery and the plate separation doubled. How much work does one have to do to pull the plates apart.
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is...
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False. 1. After being disconnected from the battery, inserting a dielectric with ? will decrease U. 2.With the capacitor connected to the battery, decreasing d increases...
A dielectric-filled parallel-plate capacitor has plate area A = 10.0 cm2 , plate separation d =...
A dielectric-filled parallel-plate capacitor has plate area A = 10.0 cm2 , plate separation d = 10.0 mm and dielectric constant k = 4.00. The capacitor is connected to a battery that creates a constant voltage V = 12.5 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Part A) Find the energy U1 of the dielectric-filled capacitor. Express your answer numerically in joules. Part B) The dielectric plate is now slowly pulled out of the capacitor, which...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d =...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 8.00 mm and dielectric constant k = 2.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Find the energy U1 of the dielectric-filled capacitor. Express your answer numerically in joules. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the...