Question

1`A puck of mass 0.110 kg slides across ice in the positive
*x*-direction with a kinetic friction coefficient between
the ice and puck of 0.167. If the puck is moving at an initial
speed of 15.0 m/s, find the following.

(a) What is the force of kinetic friction? (Indicate the
direction with the sign of your answer.)

N

(b) What is the acceleration of the puck? (Indicate the direction
with the sign of your answer.)

m/s^{2}

(c) How long does it take for the puck to come to rest?

s

(d) What distance does the puck travel during that time?

m

(e) What total work does friction do on the puck?

J

(f) What average power does friction generate in the puck during
that time?

W

(g) What instantaneous power does friction generate in the puck
when the velocity is 4.00 m/s?

W

Answer #1

given that

m = 0.110 kg

kinetic friction coefficient between the ice and puck
u_{k} = 0.167.

u = 15 m/s

(a)

F_{k} = u_{k}*N

N = m*g

F_{k} = u_{k}*m*g

F_{k} = 0.167*0.110*9.8

F_{k} = 0.180 N ( - x direcction)

(b)

we know that

F_{k} = -m*a

0.180 = -0.110*a

a = -1.63 m/s^2 (+x direction)

(c)

given v = 0

v = u+a*t

0 = 15-1.63*t

t = 9.20 s

(d)

s = u*t-1/2*a*t^2

s = 15*9.20 -0.5*1.56*9.20*9.20

s = 71.99 m

(e)

W = F_{k}*s

W = 0.180 * 71.99

W = 12.95 J

(f)

P = dW /dt = 12.95 / 9.20

P= 1.40 W

(g)

P = F*v

P = 0.180 *4

P = 0.72 W

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