Question

# You pour out 276 g of tea, (specific heat c = 1.00 c a l g...

You pour out 276 g of tea, (specific heat c = 1.00 c a l g K, same as H2O), pretty hot to start, T i =349 K. However, you also want to sweeten it with some honey, mass m h =152g, right out of the refrigerator at temperature T i = 277 K. Honey's specific heat is c = 0.64 c a l g K.

Calculate the thermal equilibrium of the tea with honey.

Type in the equilibrium temperature to the nearest Kelvin. E.g., if your answer it 233.588 K, then type in 234.

According to principle of mixtures,

Heat lost by tea= Heat gained by Honey

Mt- Mass of tea

Mh- mass of honey

Ct- specific heat capacity of tea

Ch- specific heat capacity of honey

Tt- temperature of tea

Th - temperature of honey

T- equilibrium temperature

Mt* Ct*(Tt- T) = Mh*Ch*(T-Th)

Mt*Ct*Tt- Mt*Ct*T= Mh*Ch*T- Mh*Ch*Th

T= (Mt*Ct*Tt + Mh*Ch*Th)/(Mt*Ct+ Mh*Ch)

T= ((276*1*349)+ (152*0.64*277))/((276*1)+(152*0.64)) = 123270.56/373.28= 330.23

So Equilibrium temperature is 330 K

#### Earn Coins

Coins can be redeemed for fabulous gifts.

##### Need Online Homework Help?

Most questions answered within 1 hours.

##### Active Questions
• Mr. Conrado Aristi faces the following decision: The National Medical Federation wanted to use his hotel...
• Given 3.0 mL of 3-methyl-1-butanol how would I synthesize the derivative Naphthylurethane. Please provide a detailed...
• A point charge q1 = 3.05 nC is located on the x-axis at x = 2.30...
• Identify and describe three different problem solving strategies. Suggest how each strategy might be fruitfully applied...
• There are many issues affecting organizations today, such as employee retention, flexible work schedule, contingent workforce,...
• Sammy's is the hot new lunch spot among the hipsters, who flock there at noon for...