Consider a pipe with a length of 37.5 cm. If the temperature of the air is 14.5 °C and the pipe is closed at one end and open in the other, what is the frequency of the third harmonic (also called the 2nd overtone) for the pipe?
Post your answer in hertz (Hz) and with 3 significant figures.
ANS : GIVEN : L = 37.5 cm = 37.5 x 10-2 m , velocity of sound V = 340 m /sec (AT 14.5 0c )
in this problem f 3 = 3V / 4L
f3 =( 3 x 340 ) / 4 x 37,5 x 10-2
f 3 = (1020 x100) / (150)
f3 = 680 Hz
i,e the frequency of third harmonic for the pipe is f3 = 680 Hz
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