Question

The radioactive isotope 198Au has a half-life of 64.8 hr. A sample containing this isotope has an initial activity (t = 0) of 1.5x 10^12 Bq. Calculate the number of nuclei that decay in the time interval between t1 = 10 hr and t2 = 12 hr.

Please show and explain work, and do not use calculus to solve it.

Answer #1

The radioactive isotope 198Au has a half-life of 64.8 hours. A
sample containing this isotope has an initial activity at (t=0) of
1.50e-12 Bq. Calculate the number of nuclei that will decay in the
time interval between t1=10 hours and t2=20 hours
Answer is 4.60e16 but I'm not sure how. Thanks and please show
work

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___________ Nuclei

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