The figure shows a cross section across a long cylindrical conductor of radius a = 1.99 cm carrying uniform current 24.7 A. What is the magnitude of the current's magnetic field at radial distance (a) 0, (b) 1.43 cm, (c) 1.99 cm (wire's surface), (d)3.13 cm?
Solution;
a= 1.99 cm = 0.0199 m
I= 24.7 A
A)
When r= 0
Then the magnitude B is
B=0 T
B) when r= 1.43 cm
Then the magnitude B is
C) when r=1.99 cm on surface then the magnitude B is
d)
When r= 3.13 cm
Then the magnitude of B is
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