Question

The figure shows a cross section across a long cylindrical
conductor of radius *a* = 1.99 cm carrying uniform current
24.7 A. What is the magnitude of the current's magnetic field at
radial distance **(a)** 0, **(b)** 1.43
cm, **(c)** 1.99 cm (wire's surface),
**(d)**3.13 cm?

Answer #1

Solution;

a= 1.99 cm = 0.0199 m

I= 24.7 A

A)

When r= 0

Then the magnitude B is

B=0 T

B) when r= 1.43 cm

Then the magnitude B is

C) when r=1.99 cm on surface then the magnitude B is

d)

When r= 3.13 cm

Then the magnitude of B is

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