A five-slit system with 9.0 μm slit spacing is illuminated with 645 nm light.
Part A
Find the angular positions of the first two maxima.
Enter your answers numerically separated by a comma.
|
||||
θ1,θ2 = .... degree Part B Find the angular positions of the third and sixth minima. Enter your answers numerically separated by a comma.
|
here d = 9um = 9 x 10-6 m lemda = 645nm = 645 x 10-9 m
(a) for the m,axima
d sinQ = n(lemda)
for first maxima n = 1
so sinQ1 = ( 1 x 645 x 10-9 ) / ( 9 x 10-6 )
= 0.0716
Q1 = sin-1(0.0716) = 0.0717o Ans
for second maxima n = 2
d sinQ2 = 2 x 645 x 10-9
sinQ2 = 0.1433
Q2 = sin-1(0.1433) = 0.1438o Ans
(b) for the minima
d sinQ = ( n + 1/2 ) lemda
for third minima n = 3
sinQ3 = ( 3 + 0.5 ) x ( 645 x 10-9 ) / ( 9 x 10-6 )
= 0.2508
Q3 = sin-1(0.2508) = 0.253o Ans
for the sixth minima n = 6
d sinQ6 = 6.5 x 645 x 10-9
sinQ6 = 0.4658
Q6 = sin-1(0.4658) = 0.484o Ans
Get Answers For Free
Most questions answered within 1 hours.