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To what temperature would an aluminum ring have to be heated to make its diameter 1.2%...

To what temperature would an aluminum ring have to be heated to make its diameter 1.2% larger than it is at 20 oC?

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Answer #1

We need to increase the diameter of the aluminum ring from Lo  to 1.012Lo. That is an increase of

L = 0.012Lo

we find that the coefficient of thermal expansion for aluminum is

= 24 x 10 - 6 (Co) - 1

L = LoT

T = [L ] / [ Lo ]

T = 0.012Lo/ [ ( 24 x 10 - 6 (Co) - 1 ) Lo]

T = 500 Co

Tf = 520 oC

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