Question

A block with mass m = 14.6 kg slides down an inclined plane of slope angle 15.8 ° with a constant velocity. It is then projected up the same plane with an initial speed 4.35 m/s. How far up the incline will the block move before coming to rest?

Answer 1

Here, frictional force = mgsin15.8

                               = 14.6 * 9.8 * sin15.8

                               = 38.96 N

Applying conservation of energy

=> 1/2 * 14.6 * 4.35² - 38.96 * s = 14.6 * 9.8 * sin15.8 * s

=> s = 1.773 m

Thus, far up the incline will the block move before coming to rest =   1.773 m