Question

QUESTION When an electron is released from rest in a constant
electric field, how does the electric potential energy associated
with the electron, and the kinetic energy of the electron, change
with time? (Select all that apply.)

options:The electric potential energy becomes more negative.The
electric potential energy becomes more positive.The kinetic energy
becomes more negative.The kinetic energy stays the same.The
electric potential energy stays the same.The kinetic energy becomes
more positive.

Use the worked example above to help you solve this problem. A
proton is released from rest at *x* = -2.90 cm in a constant
electric field with magnitude 1.49 10^{3} N/C,
pointing in the positive *x*-direction.

**(a)** Calculate the change in potential energy when
the proton reaches *x* = 5.34 cm.

**(b)** An electron is now fired in the same
direction from the same position. What is its change in electric
potential energy if it reaches *x* = 12.50 cm?

**(c)** If the direction of the electric field is
reversed and an electron is released from rest at *x* = 3.40
cm, by how much has its electric potential energy changed when it
reaches *x* = 7.10 cm?

Find the change in electric potential energy associated with the
electron in part (b) as it goes on from *x* = 0.125 to
*x* = -0.018 m. (Note that the electron must turn around and
go back at some point. The location of the turning point is
unimportant, because changes in potential energy depend only on the
end points of the path.)

Answer #1

Solution in the uploaded image

An electron is initially at rest in a uniform electric field
having a strength of 1.95 × 106 V/m. It is then released
and accelerated by the presence of the electric field.
What is the change in the electron’s kinetic energy, in
kiloelectron volts, if it travels over a distance of 0.25 m in this
field?
Over how many kilometers would it have to be accelerated in the
same electric field to increase its kinetic energy by 65 GeV?
&...

A uniform electric field of magnitude 364 N/C pointing in the
positive x-direction acts on an electron, which is
initially at rest. The electron has moved 3.00 cm.
(a) What is the work done by the field on the electron?
(b) What is the change in potential energy associated with the
electron?
(c) What is the velocity of the electron? Magnitude (m/s) ?
Direction (+x, -x, -y, +y)?

A proton is released from rest in a uniform electric field of
magnitude 1.33×105 N/C . Find the speed of the proton after it has
traveled (a) 1.40 cm and (b) 13.0 cm .

proton is released from rest inside a region of constant,
uniform electric field E1 pointing due North. 34.8 seconds after it
is released, the electric field instantaneously changes to a
constant, uniform electric field E2 pointing due South. 9.33
seconds after the field changes, the proton has returned to its
starting point. What is the ratio of the magnitude of E2 to the
magnitude of E1? You may neglect the effects of gravity on the
proton.

A proton and an electron are released from rest at the same time
from the midpoint between two charged parallel plates. The plates
are charged with equal surface charge densities of opposite signs.
Ignore the interaction between the electron and the proton and
consider only the interaction of each charge with the electric
field of the plates. After being released, the proton will
accelerate toward the negative plate, and the electron will
accelerate toward the positive plate.
a)
Which charge...

A proton is acted on by an uniform electric field of magnitude
443 N/C pointing in the negative x direction. The particle
is initially at rest.
(a) In what direction will the charge move?
---Select--- +x direction ?x direction +y direction ?y direction +z
direction ?z direction
(b) Determine the work done by the electric field when the particle
has moved through a distance of 3.15 cm from its initial
position.
J
(c) Determine the change in electric potential energy...

An electron at rest in a vacuum is accelerated by a momentary
electric field E = 438 V/m y for
325 microseconds*. Then it enters a magnetic field of
B = 257 microTesla* x. Determine
the direction of the initial force that the electron feels when it
enters the magnetic field.
* refers to the units of time and magnetic field. Bold
in 'x' and 'y' refers to the axis/direction.

1. If an electron is accelerated from rest through an electric
potential of 200 volts, a.determine the final speed of the
electron
b. through what electrical potential must we accelerate an
electron such that it's kinetic energy is equal to its rest mass
energy?
c. An electron is traveling at a speed of 10,000m/s. What is the
kinetic energy of the electron in eV?

A proton is acted on by an uniform electric field of magnitude
313 N/C pointing in the negative y direction. The particle is
initially at rest. (a) In what direction will the charge move? (b)
Determine the work done by the electric field when the particle has
moved through a distance of 2.45 cm from its initial position. J
(c) Determine the change in electric potential energy of the
charged particle. J (d) Determine the speed of the charged
particle....

When an electron moves from rest against a uniform electric
field a distance of 10.0 cm it attains a speed v. If it moves an
additional 10.0 cm, the final speed is:
Select one: 1.4 v
0.7 v
2.0 v
v
4.0 v

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