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What is the nuclear binding energy of iron-56 (56Fe)? Show ALL work, including set up.

What is the nuclear binding energy of iron-56 (56Fe)? Show ALL work, including set up.

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Answer #1

no of prorotns, z = 26

no of nuetrons, N = 56 - 26

= 30

mass of Iron nucleus, M = 55.9349375 u

= 55.9349375*1.660540*10^-27 kg

= 9.2882201*10^-26 kg

mass of protosn, Mp = z*mp

= 26*1.6726219*10^-27 kg

= 4.34881694*10^-26 kg

mass of nutrons, Mn = N*mn

= 30*1.67492747*10^-27

= 5.02478241*10^-26 kg

mass defect, delta_m = (Mp + Mn - M)

= (4.34881694*10^-26 + 5.02478241*10^-26 - 9.2882201*10^-26)

= 8.537925*10^-28 kg

binding energy, E = delta_m*c^2

= 8.537925*10^-28*(3*10^8)^2

= 7.684*10^-11 J

= 7.684*10^-11/(1.6*10^-19)

= 480*10^6 eV

= 480 MeV

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