Question

Part A

Compute the impedance of a series R-L-C circuit at angular frequencies of ω1= 1000 rad/s , ω2= 750 rad/s and ω3= 550 rad/s . Take R = 225 Ω , L = 0.885 H and C = 1.75 μF .

Enter your answers as three numbers separated with commas.

Z1, Z2, Z3 =386,245,596 (correct answers) ONLY ANSWER PART B AND C, possible part D.... hanks

  Ω  

Part B

Describe how the current amplitude varies as the angular frequency of the source is slowly reduced from 1000 rad/s to 550 rad/s .

Describe how the current amplitude varies as the angular frequency of the source is slowly reduced from 1000  to 550  .

Amplitude is always constant.

Amplitude decreases.

Amplitude increases.

First amplitude increases next it decreases.

First amplitude decreases next it increases.

Part C

What is the phase angle of the source voltage with respect to the current when ω = 1000 rad/s?

ϕ =

  ∘

Answer 1

first you nees to find resonance frequency

w_o  = 1/( LC)^0.5   = 803.5 rad/s

After puting value of L and C

Describe how the current amplitude varies as the angular frequency of the source is slowly reduced from 1000 rad/s to 550 rad/s

Impedance is minimum at resonance frequency and if you moving high in frequency and low in frequency both sides will increases the impedance compared to the resonance point 803.5 rad/s

Therefore answer is : First amplitude decreases next it increases.

same thing when you go from 550 to 1000

What is the phase angle of the source voltage with respect to the current when ω = 1000 rad/s?

X_L = wL 1000 * 0.885 = 885 ohm

X_C  = 1/wC = 571.43 ohm

Putting value

= 54.34^o