Question

A diverging lens has a focal length of magnitude 21.8 cm.

(a) Locate the images for each of the following object distances.
43.6 cm

distance	cm
location	---Select--- in front of the lens behind the lens

21.8 cm

distance	cm
location	---Select--- in front of the lens behind the lens

10.9 cm

distance	cm
location	---Select--- in front of the lens behind the lens

(b) Is the image for the object at distance 43.6 real or virtual?

realvirtual    

Is the image for the object at distance 21.8 real or virtual?

realvirtual    

Is the image for the object at distance 10.9 real or virtual?

realvirtual    

(c) Is the image for the object at distance 43.6 upright or inverted?

uprightinverted    

Is the image for the object at distance 21.8 upright or inverted?

uprightinverted    

Is the image for the object at distance 10.9 upright or inverted?

uprightinverted    

(d) Find the magnification for the object at distance 43.6 cm.


Find the magnification for the object at distance 21.8 cm.


Find the magnification for the object at distance 10.9 cm.

Answer 1

(b) 1. Virtual

2. Virtual

3. Real

(c) m = v/u

1. Erect/ Upright

2. Upright

3. Inverted

(d) m = v/u

1. m = -43.6/-43.6 = 1. Magnification = 1.

2. infinity.

3. m = 21.8 / -10.9 = -2. Magnification = -2.