Question

a particle of charge q=5.9×10^-3 coulombs is initially located towards the middle of a pair of a parallel plated with an electric field of magnityde E=5.4×10^2v/m. the plate are separated by distance 6.7×10^-2m. the particle is moved from its intial location at the bottom plate to its final location at top plate . find the total work fone in units of joules.

Answer 1

Here we have given that,

a particle of charge q=5.9×10^-3 coulombs

electric field of magnityde E=5.4×10^2v/m

The plates are separated by distance 6.7×10^-2 m

So that here Voltage difference between the plates will be given as,

V = E×d = 5.4 ×10² × 6.7 ×10^-2 = 36.18 V

Now when the particle is moved from its intial location at the bottom plate to its final location at top plate then for the total work fone in units of joules we have the relation as,

W = q V = 5.9 × 10^-3 × 36.18

W = (0.213462) J

Which is the required amount of work done here.