A circuit consists of two resistors, 1.80 Ω and 9.79 Ω, connected in series. The combination of resistors is connected to a 12.0 V battery. Calculate a) the equivalent resistance of the circuit, b) the current in the circuit, and c) the total power usage of the circuit.
let
R1 = 1.80 ohms
r2 = 9.79 ohms
V = 12.0 V
a) the equivalent resistance of the circui,
Req = R1 + R2
= 1.80 + 9.79
= 11.6 ohms <<<<<<<<<<<-----------------Answer
b) the current in the circuit, I = V/Req
= 12/11.6
= 1.03 A <<<<<<<<<<<-----------------Answer
c) the total power usage of the circuit, P = I^2*Req
= 1.03^2*11.6
= 12.3 W <<<<<<<<<<<-----------------Answer
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