Question

A circuit consists of two resistors, 1.80 Ω and 9.79 Ω, connected in series. The combination of resistors is connected to a 12.0 V battery. Calculate a) the equivalent resistance of the circuit, b) the current in the circuit, and c) the total power usage of the circuit.

Answer 1

let
R1 = 1.80 ohms
r2 = 9.79 ohms
V = 12.0 V

a) the equivalent resistance of the circui,

Req = R1 + R2

= 1.80 + 9.79

= 11.6 ohms <<<<<<<<<<<-----------------Answer

b) the current in the circuit, I = V/Req

= 12/11.6

= 1.03 A <<<<<<<<<<<-----------------Answer

c) the total power usage of the circuit, P = I^2*Req

= 1.03^2*11.6

= 12.3 W <<<<<<<<<<<-----------------Answer