Question

A circuit consists of two resistors, 1.80 Ω and 9.79 Ω, connected in series. The combination of resistors is connected to a 12.0 V battery. Calculate a) the equivalent resistance of the circuit, b) the current in the circuit, and c) the total power usage of the circuit.

Answer #1

**let
R1 = 1.80 ohms
r2 = 9.79 ohms
V = 12.0 V**

**a) the equivalent resistance of the circui,**

**Req = R1 + R2**

**= 1.80 + 9.79**

**= 11.6 ohms
<<<<<<<<<<<-----------------Answer**

**b) the current in the circuit, I = V/Req**

**= 12/11.6**

**= 1.03 A
<<<<<<<<<<<-----------------Answer**

**c) the total power usage of the circuit, P =
I^2*Req**

**= 1.03^2*11.6**

**= 12.3 W
<<<<<<<<<<<-----------------Answer**

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