Question

A particle with a charge of −1.24E-8 C is moving with instantaneous velocity v⃗  = (4.19E4 m/s)(i)...

A particle with a charge of −1.24E-8 C is moving with instantaneous velocity v⃗  = (4.19E4 m/s)(i) + (−3.85E4 m/s )(j).

What is the force exerted on this particle by a magnetic field B= (1.50 T ) (i)? Forces in x, y, and z.

What is the force exerted on this particle by a magnetic field B= (1.50 T ) (k)? Forces in x, y, and z.

Please show ALL work.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v⃗ = (4.19×104m/s)i^ +...
A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v⃗ = (4.19×104m/s)i^ + (−3.85×104m/s)j^ . Part A What is the force exerted on this particle by a magnetic field B⃗  = (1.40 T ) i^? Enter the x, y, and z components of the force separated by commas. Part B What is the force exerted on this particle by a magnetic field B⃗  = (1.40 T ) k^? Please solve and show how you get the z component from...
A particle with a charge of −−1.24××10−8C−8C is moving with instantaneous velocity v⃗ v→ = (4.19××104m/s4m/s)i^i^...
A particle with a charge of −−1.24××10−8C−8C is moving with instantaneous velocity v⃗ v→ = (4.19××104m/s4m/s)i^i^ ++ (−−3.85××104m/s4m/s)j^j^ . 1)What is the force exerted on this particle by a magnetic field B⃗ B→ = (2.70 TT ) i^i^? Enter the xx, yy, and zz 2)What is the force exerted on this particle by a magnetic field B⃗ B→ = (2.70 TT ) k^k^? Enter the xx, yy, and zz
A particle with charge −− 5.80 nCnC is moving in a uniform magnetic field B⃗ =−(B→=−(...
A particle with charge −− 5.80 nCnC is moving in a uniform magnetic field B⃗ =−(B→=−( 1.20 TT )k^k^. The magnetic force on the particle is measured to be F⃗ =−(F→=−( 3.50×10−7 NN )i^+()i^+( 7.60×10−7 NN )j^)j^. A) Calculate the x-component of the velocity of the particle. B) Calculate the y-component of the velocity of the particle. C) Calculate the scalar product v⃗ ⋅F⃗ v→⋅F→. D) What is the angle between v⃗ v→v_vec and F⃗ F→?
A particle with charge − 5.10 nC is moving in a uniform magnetic field B⃗ =−(...
A particle with charge − 5.10 nC is moving in a uniform magnetic field B⃗ =−( 1.25 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^ . Part A Are there components of the velocity that are not determined by the measurement of the force? yes no Part D Calculate the scalar product v⃗ ⋅F⃗. v⃗ ⋅F⃗ m/s⋅N Request Answer Part E What is the angle between v⃗ and...
A particle moving in the xy-plane has velocity v⃗ =(2ti+(3−t2)j)m/s, where t is in s. What...
A particle moving in the xy-plane has velocity v⃗ =(2ti+(3−t2)j)m/s, where t is in s. What is the x component of the particle's acceleration vector at t = 7 s? What is the y component of the particle's acceleration vector at t = 7 s?
A particle with a charge of − 5.20 nC is moving in a uniform magnetic field...
A particle with a charge of − 5.20 nC is moving in a uniform magnetic field of B⃗ =−( 1.21 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 3.70×10−7 N )i^+( 7.60×10−7 N )j^. Calculate the scalar product v⃗ ⋅F⃗ . Work the problem out symbolically first, then plug in numbers after you've simplified the symbolic expression.
A charged particle of mass m = 4.6X10-8 kg, moving with constant velocity in the y-direction...
A charged particle of mass m = 4.6X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B = 2.3T aligned with the positive z-axis as shown. The particle enters the region at (x,y) = (0.79 m, 0) and leaves the region at (x,y) = 0, 0.79 m a time t = 409 μs after it entered the region. 1. With what speed v did the particle enter the region containing the magnetic...
A small particle with positive charge q=+4.25×10^−4 C and mass m=5.00×10^−5 kg is moving in a...
A small particle with positive charge q=+4.25×10^−4 C and mass m=5.00×10^−5 kg is moving in a region of uniform electric and magnetic fields. The magnetic field is B=4.00 T in the +z-direction. The electric field is also in the +z-direction and has magnitude E=60.0 N/C. At time t = 0 the particle is on the y-axis at y=+1.00 m and has velocity v = 30.0 m/s in the +x-direction. Neglect gravity. What are the x-, y-, and z-coordinates of the...
A particle with charge - 5.60 nC is moving in a uniform magnetic field B =...
A particle with charge - 5.60 nC is moving in a uniform magnetic field B = -J 1.25 T) k. The magnetic force on the particle is measured to be F = - (3.40 X l0-7 N) i+ (7.40 X l0-7 N) j.(a) Calculate all the components of the velocity of the particle that you can from this information.(b) Are there components of the velocity that are not determined by the measurement of the force? Explain.(c) Calculate the scalar product...
A particle with a charge of − 5.30 nCnC is moving in a uniform magnetic field...
A particle with a charge of − 5.30 nCnC is moving in a uniform magnetic field of B⃗ =−(B→=−( 1.25 TT )k^k^. The magnetic force on the particle is measured to be F⃗ =−(F→= −( 3.00×10−7 NN )i^+()i^+( 7.60×10−7 NN )j^)j^. What is the angle between v⃗ v→v_vec and F⃗ F→F_vec? Express your answer in degrees to three significant figures.