Question

A small fluffy stuffed animal was accidentally left on a merry-go-round. The stuffed animal is a...

A small fluffy stuffed animal was accidentally left on a merry-go-round. The stuffed animal is a distance 4.7 m from the center of the ride. Suddenly, the operator turns on the ride and it quickly begins spinning at 6.13666568105649 s per revolution. What is the least coefficient of static friction between the animal and the ride to prevent it from slipping?

Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Given that:

Radius r = 4.7 m

Time per revolution T = 6.13666568105649 sec

Mass of the stuffed animal = m

coefficient of static friction =

Angular speed =

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
At a playground, a 17-kg child sits on a spinning merry-go-round, as shown from above in...
At a playground, a 17-kg child sits on a spinning merry-go-round, as shown from above in (Figure 1).The merry-go-round completes one revolution every 6.2 s, and the child sits at a radius of r=1.8m. Part A What is the force of static friction acting on the child? Express your answer to two significant figures and include appropriate units. Part B What is the minimum coefficient of static friction between the child and the merry-go-round to keep the child from slipping?
Billy (mass = 50 kg) stands on the edge of a merry-go-round, which is a disc...
Billy (mass = 50 kg) stands on the edge of a merry-go-round, which is a disc with a radius R = 2.0 m and a mass M = 100 kg. Annie begins spinning the merry-go-round (and Billy) by pushing on it with a force of 20 N tangent to its edge for 20 s. (a) What are (i) the torque Annie imparts on the merry-go-round (with Billy on it) and (ii) the resulting angular acceleration during the 20 second interval?...
Laurel and Hardy are sitting on a merry-go-round while it turns at a steady speed. Laurel...
Laurel and Hardy are sitting on a merry-go-round while it turns at a steady speed. Laurel weighs 2/3 of what Hardy weighs. Hardy is sitting twice as far from the center as Laurel. Both Laurel and Hardy are just on the verge of slipping. Which statement below correctly describes the relation of their coefficients of friction? A) Laurel’s coefficient is twice as big as Hardy’s. B) Hardy’s coefficient is twice as big as Laurel’s.                       C) Laurel’s coefficient is 3 times...
. A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it...
. A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to 15 rpm in 10.0 seconds. The merry-go-round has a radius of 2.5m and mass of 560 kg and his two kids (each 25 kg) sit on opposite sides of each other on the edge. (a) Calculate the magnitude of the dad’s pushing force on the edge of the merry-go-round. (b) After these 10.0 seconds, the dad stops pushing. One kid quickly...
A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from...
A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to 15 rpm in 10.0 seconds. The merry-go-round has a radius of 2.5m and mass of 560 kg and his two kids (each 25 kg) sit on opposite sides of each other on the edge. (a) Calculate the magnitude of the dad’s pushing force on the edge of the merry-go-round. (b) After these 10.0 seconds, the dad stops pushing. One kid quickly steps...
A large turntable (a merry-go-round) is able to rotate with friction about a fixed vertical axis...
A large turntable (a merry-go-round) is able to rotate with friction about a fixed vertical axis through its center. The moment of inertia of the turntable about this axis is 1300  kg⋅m2 . A daring child, with a mass of 40.0  kg , is riding the merry-go-round while wearing roller skates. She is initially standing at the center of the turntable (and spinning with the turntable); at this time, the turntable is making one revolution every 6.50  seconds . The adventurous child finds...
1) You wish to accelerate a small merry-go-round from rest to a rotational speed of one-fourth...
1) You wish to accelerate a small merry-go-round from rest to a rotational speed of one-fourth of a revolution per second by pushing tangentially on it. Assume the merry-go-round is a disk with a mass of 300 kg and a radius of 2.00 m . Ignoring friction, how hard do you have to push tangentially to accomplish this in 6.00 s ? (Use energy methods and assume a constant push on your part.) F=? 2) A person opens a door...
the dogs are at bell's amusement park. maxwell is on the tilt-a-whirl (a merry go round...
the dogs are at bell's amusement park. maxwell is on the tilt-a-whirl (a merry go round type machine that initially spins horizontally around a vertical axis with passengers pressed against its exterior walls. it does this without passengers falling out.) the tilt-a-whirl is six meters (6m) in diameter. fifty kilogram (50kg) maxwell is 2.0 meters from the tilt-a-whirls center and the coefficient of static friction between the maxwell and the tilt-a-whirls floor is 0.20. the tilt-a-whirl has an old motor...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT