Question

(a)

What frequency (in Hz) is received by a person watching an oncoming ambulance moving at 106 km/h and emitting a steady 850 Hz sound from its siren? The speed of sound on this day is 345 m/s.

Hz

(b)

What frequency (in Hz) does she receive after the ambulance has passed?

Hz

Answer #1

So we have Fa = (U + V)/(V/Fs) = Fs (U/V + 1) = 850*(29.44/345 + 1)
= 922.533 c/s. ANS. a.

And after passing w = V - U is the relative speed of the wave with
L. So the apparent period is T = L/w and the apparent frequency fa
= 1/T = w/L = (V - U)/(V/Fs) = Fs (1 - U/V) = 850*(1 - (29.44)/345)
= 777.466 cps ANS. b.

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