Question

Three 102.0-g ice cubes initially at 0°C are added to 0.810 kg of water initially at...

Three 102.0-g ice cubes initially at 0°C are added to 0.810 kg of water initially at 18.0°C in an insulated container.

(a) What is the equilibrium temperature of the system?

(b) What is the mass of unmelted ice, if any, when the system is at equilibrium?

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Homework Answers

Answer #1

heat lost by water in melting ice to 0deg water Qloss = Mw*Sw*(18-0) = = 61031.88 J


heat required to convert ice at 0 to water at 0 Qreq = Mice*L = 3*0.102*334*10^3 = 102204 J

all the ice melts will not melt


(a)


some ice is unmelted


the equilibrim temperatre is 0oC   <<<+=====ANSWER

(b)


let m kg of ice melts


In equilibrium


heat loss by water = heat gained by m kg of ice

heat loss by water = Mw*Sw*(18)

m*L = Mw*Sw*18

m*334*10^3 = 0.81*4186*18

m = 0.183 kg


mass of ice unmelted = (3*0.102) - 0.183 = 0.123 kg   <<<+=====ANSWER

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