A 15-kg metallic cube with uniform density is immersed to a depth of 2.0 m in a lake. If a buoyant force of 49 N acts
on the cube, what is the density (in kg/m3) of the metal? Answer: 3000
Given,
The mass, m = 15 kg
The buoyant force, FB = 49 N
The buoyant force on block = The weight of displaced water
FB = Wd
FB = Vw g ( V = m/)
FB = (m/m) * w * g
m = (m * w * g) / FB
= (15 * 1000 * 9.8) / 49
= 3000 kg/m3
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