Question

A 200 g block of copper at a temperature of 75°C is dropped into 650 g of water at 35°C. The water is contained in a 400 g glass container. What is the final temperature of the mixture?

Answer #1

Heat loss by the copper will be gained by the glass-water system since the system is assumed to be isolated. Thus if T is the final temperature of the system,we'll have

where m_{c}= mass of copper=200g

c_{c}= specific heat of copper,

T_{c}= Initial temperature of the copper

m_{w}= mass of water= 650g

c_{w}= specific heat of water,

m_{g}= mass of glass container= 400g

c_{g}= specific heat of glass,

Then using all above and given values in above equation,

**(ANS)**

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