Question

1- You’re on a Ferris wheel moving in a vertical circle. When the Ferris wheel is at rest, the

normal force N exerted by your seat is equal to your weight mg. How does N change at the top

of the Ferris wheel when you are in motion?

a- N remains equal to mg

b- N is smaller than mg

c- N is larger than mg

d- None of the above

2- You’re on a Ferris wheel moving in a vertical circle. When the Ferris wheel is at rest, the

normal force N exerted by your seat is equal to your weight mg. How does N change at the

bottom of the Ferris wheel when you are in motion?

a- N remains equal to mg

b- N is smaller than mg

c- N is larger than mg

d- None of the above

3- Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of

rotation than child B. Which child has the larger linear velocity?

a. Child A

b. Child B

c. They have the same zero angular displacement. d. They have the same angular displacement. e. There is not enough information given to answer the question.

4- Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of

rotation than child B. Which child has the larger linear displacement?

a. Child A

b. Child B

c. They have the same zero angular displacement. d. They have the same angular displacement. e. There is not enough information given to answer the question.

Answer 1

Q1.

at the top, N and m*g are working in same direction and are balanced by centripetal force m*v^2/r

hence N+m*g=m*v^2/r

=>N=(m*v^2/r)-m*g

without knowing the speed and radius, nothing can be commented

about relation between N and m*g.

hence option d is correct.

Q2.

at the bottom,

N=(m*v^2/r)+m*g

hence N>m*g

option c is correct.

Q3. linear velocity=angular velocity*radius

hence as child A has a greater distance from the axis of rotation,

child A has greater linear velocity

hence option A is correct.

Q4.

larger the distance from axis, larger will be linear displacement.

hence option A is correct.