Question

How much heat is required to convert solid ice with a mass of 605 g at a temperature of -22.5 °C to liquid water at a temperature of 65.0 °C? The specific heat of ice is c_ice = 2100 J/kgK, the specific heat of water is c_water = 4186.8 J/kgK, and the heat of fusion for water is L_f = 334 kJ/kg.
(in J)

Answer 1

Given

Mass of ice , m= 605 g =0.605 kg

The specific heat of ice , 2100 J/kgK

the specific heat of water , 4186.8 J/kgK

the heat of fusion for water , 334 kJ/kg= J/kg.

Explanation:

Now amount of heat gained by m=0.605 kg of ice at -22.5°C to raise its temperature to 0°C is given by,

Now amount of heat gained by 0.605 kg of ice at 0°C to convert into water at 0°C is given by,

Amount of heat energy gained when temperature of 0.605 kg of water at 0°C rises to 65.0°C is given by,

Total amount of heat energy required is ,

Ans:

So the amount of heat required to convert that amount of ice to temperature at 65°C is 395302.16 J.