The position of a particle moving along the x axis depends on the time according to the equation x = ct2 − bt3, where x is in meters and t in seconds.
For the following, let the numerical values of c and b be 5.1 and 1.5, respectively. (For vector quantities, indicate direction with the sign of your answer.)
(c) At what time does the particle reach its maximum positive
x position? From t = 0.0 s to t = 4.0 s,
what distance does the particle move?
(e) From t = 0.0 s to t = 4.0 s, what is its displacement?
(c) Maximum positive x position reaches at t = 1.505 s.
Distance travelled between t=0, t=4s is D = 27.22 m.
(e.) Maximum displacement = 14.4 m. ( in -x direction)
Get Answers For Free
Most questions answered within 1 hours.