Question

Carrollton, GA is 335 meters above sea level. What is the atmospheric pressure in Carrollton? (The density of air is 1.29 kg/m3.)

Answer 1

Answer:

Given, altitude h = 335 m

Atmospheric pressure p with respect to altitude h in troposphere region.

   p = 2116 x [(T + 459.7) / 518.6]5.256 , where pressure is in lb/ft2, altitude is in ft and temperature T in 0F

here T = 59 - 0.00356 h

Now, h = 335 m = 335 x 3.281 ft = 1099.13 ft. Since 1 m = 3.281 ft.

Therefore, T = 59 - 0.00356 (1099.13 ft) = 55.08 0F

Then, atmospheric pressure at the altitude h is p = 2116 x [(55.08 + 459.7) / 518.6]5.256 = 2035.35 lb/ft2.

Unit conversion:

1 psi = 144 lb/ft2 and 1 psi = 0.0680 atm

Then, p = (2035.35) / 144 psi = 14.134 psi = (14.134) (0.0680 atm) = 0.961 atm.

1 atm = 101325 Pa (Pascal)

p = 0.961 x 101325 Pa = 97373.32 Pa.

Pressure at sea level is p = 101325 pa or 1 atm

Hence, the atomospheric pressure decreases with altitude and the atmospheric pressure at Carrollton is 0.961 atm or 97373.32 Pa.