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The electric field strength between two parallel conducting plates separated by 3.00 cm is 7.0 x...

The electric field strength between two parallel conducting plates separated by 3.00 cm is 7.0 x 10^4 V/m. What is the potential difference between the plates?

Please include a picture, and show work pls!!! I need to understand this!!!

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Answer #1

electric field = E = 7 X 10^4 V/m

distance = 3 cm = 0.03 m

potential difference (V) = ?

                   E = V / d

                   (V) = E * d   = 7 X 10^4 * 0.03 = 2100 Volts

                  

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