Question

The sun is 35 degrees above the horizon over a perfectly still lake.a bear decides he wants to go fishing for his food today. Standing with his eyes 2.0 meters above the lake and standing 0.50 meters from the edge of the lake, the Bear sees a fish in the water in the water. If the fish is 0.35 meters deep under the water. How far away from Bear does the fish appear?

Answer 1

Optics of Reflection and Refraction are mostly governed by laws of reflection and refraction .

Laws of refraction :

1. The normal , incident ray and the reflected ray all lie at the same plane .
2. Angel of reflection and incidence are equal.

Laws of Refraction

1. The normal , incident ray and the refracted ray all lie at the same plane .
2. Sine of angle of incidence and refraction bears a constant ratio.(Snell's Law)

Angle of Incination of sun = 35o ABM= 55O Using Snell's law M`BC=38o And light gets reflected at C So, we can obtain other angles as shown.

Now OC = 0.35m OD/OC = tan38o

So OD=0.27m and OP=0.27+0.5 =0.77m

So, vertically the bear see the fish at X . OX = 0.35/1.33=0.26m