Question

5. At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 920 m/s2 and the vertical or y component of its acceleration is 940 m/s2. The ball's mass is 0.42 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

Answer 1

Solution:-

Newton second law – In an inertial frame of references, the vector sum of the forces F on an object is equal to the mass m of the object multiplied by the acceleration a of the object

That is, F =m*a

Given –

Horizontal component acceleration – 920 m/s^2

Vertical component acceleration – 940 m/s^2

Mass (m) = 0.42 kg

Calculate magnitude of net force

Firstly, calculate net acceleration –

√ (920) ^2 + (940) ^2 = 1315 m/s^2

So the net force, F = m*a

Where,

m= mass

a = net acceleration

Putting given values in the above equation

F = (0.42kg)*(1315 m/s^2)

F = 552 N

The magnitude of net force is 552 N