An electron is located on the x ‑axis at x 0 = − 2.51 × 10 − 6 m . Find the magnitude and direction of the electric field at x = 4.55 × 10 − 6 m on the x ‑axis due to this electron.
N / C direction: negative x ‑direction positive x ‑direction neither of these
The position of the electron is
And the position of the pint in question is
The position vector of the point w.r.t the position of the given electron is
The electric field is given by
So,
The magnitude of the electric field at the requested point is 28.89 N/C.
And the direction of the electric field is negative x-direction.
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