Question

A single slit of width .25 mm is illuminated with monochromatic light of wavelength 505nm, and...

A single slit of width .25 mm is illuminated with monochromatic light of wavelength 505nm, and a diffraction pattern is formed on a screen 2.2m away from the slit. What is the width of the central maximum? If the width were increased, how would this change affect the size of the central maximum?

Homework Answers

Answer #1

d = slit width = 0.25 mm = 0.25 x 10-3 m

= wavelength of the light = 505 nm = 505 x 10-9 m

D = screen distance = 2.2 m

w = width of the central maximum

Width of the central maximum is given as

w = 2 D/d

w = 2 (2.2) (505 x 10-9)/(0.25 x 10-3)

w = 8.89 x 10-3 m

The width of the central maximum is inversely related to width of the slit . hence as the width of the slit is increased, the width of the central maximum will decrease.

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