Question

An electron enters a magnetic field with speed v=1.41x10^6 m/s and emerges after moving in a semicircular path with a diameter 10cm. Find the magnitude and the direction of the magnetic field, and the time it took the electron to move on this path.

Answer #1

since electron moves in a circular path hence field must have been perpendicular to the direction of motion of the electron.

hence

q is the charge of electron

v is the velocity of electron

B magnetic field strenght

m is mass of electron

r is radius of the path

hence

B = perpendicular to the direction of motion of electron

time =

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Figure
1 of 1
Part A
Part complete
Find the direction of the magnetic field that will cause the
electron to follow the semicircular path from AAA to BBB.
The magnetic field must go into the page.
SubmitPrevious Answers
Correct
Part B
Find the magnitude of the magnetic field that will cause the
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