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An electron enters a magnetic field with speed v=1.41x10^6 m/s and emerges after moving in a...

An electron enters a magnetic field with speed v=1.41x10^6 m/s and emerges after moving in a semicircular path with a diameter 10cm. Find the magnitude and the direction of the magnetic field, and the time it took the electron to move on this path.

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Answer #1

since electron moves in a circular path hence field must have been perpendicular to the direction of motion of the electron.

hence

q is the charge of electron

v is the velocity of electron

B magnetic field strenght

m is mass of electron

r is radius of the path

hence

B = perpendicular to the direction of motion of electron

time =

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