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An isolated conductor has a net charge of +8.90*10^-6 C and a cavity with a particle...

An isolated conductor has a net charge of +8.90*10^-6 C and a cavity with a particle of charge q= + 4.10 * 10^-6 C. What is the charge (a) on the cavity wall and ( b) on the outer surface?
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Answer #1

(a)

which is - 4.1*10^-6C because the charge insdie a conductor has to be 0.

b)


charges on a conductor can only exist on the surfaces (like the outer surfaces, or the wall surface of an internal cavity). the problem states the total NET charge on the conductor (surfaces) is +8.90*10(-6) Coulombs.

the internal cavity surface charge to be -4.10*10(-6) C,

the remainder must be on the outer surface:

outer surface charge = (total NET charge) - (inner cavity surface charge)

= (+8.9*10(-6)) - (-4.10*10(-6))

= +13.0*10(-6) C

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