Question

1. a) Open milk box has a small hole pierced in it 5 cm below the top.As it is the hole is 7 cm above the top of the table. Find the maximum horizontal distance ( measured in centymeters at the table level) reached by the resulting stream of milk.Round your answer to the tenth of cm.

b)

Sealed juice box( closed on top) has a small hole pierced in its side wall 1/3 above its bottom.

It is later turned upside down ( so that the hole is now 2/3 above the ground)

As you observe this situation which of the following scenario will occur?

	A.	The juice will form a stream which will increase in volume as the time goes on, and it will stop abruptly. Also, the juice stream will reach larger and larger horizontal distances as the time goes on. After flipping the box this situation will repeat itself
	B.	The juice will form a stream which will decrease in strentgh as the time goes on. It will be reaching shorter and shorter horizontal distances as the time goes on until it will stop completely. After flipping the box this situation will repeat itself.
	C.	The juice will form a stream which will decrease in strentgh as the time goes on. It will be reaching shorter and shorter horizontal distances as the time goes on until it will stop completely. After flipping the box there will be no more flow.
	D.	There is not enough information to make reliable prediction.
	E.	None of the above

Answer 1

1) velocity of stream through the hole,

v = sqrt(2*g*h)

= sqrt(2*9.8*0.05)

= 0.98995 m/s

let t is the time taken for the stream to touch the table top.

use, y = voy*t + 0.5*ay*t^2

-0.07 = 0 + 0.5*(-9.8)*t^2

==> t = sqrt(2*0.07/9.8)

= 0.1195 s

Horizontal distance travelled, x = vox*t

= 0.98995*0.1195

= 0.118 m

= 11.8 cm <<<<<<<<<<---------------------Answer

b) C.   The juice will form a stream which will decrease in strentgh as the time goes on. It will be reaching shorter and shorter horizontal distances as the time goes on until it will stop completely.
After flipping the box there will be no more flow.