Question

Consider a slab of face area A and thickness L. Suppose that L = 17 cm, A = 71 cm², and the material is copper. If the faces of the slab are maintained at temperatures T_H = 116°C and T_C = 22°C, and a steady state is reached, find the conduction rate through the slab. The thermal conductivity of copper is 401 W/m·K.

Answer 1

Given data:

Thickness of slab = 17 cm = 0.17 m

Area of the slab =

Now from Fourier law of thermal conduction for steady state.

Q = Conduction rate through slab

Q = 1574.27     J/s

Conduction rate through slab is 1574.27 Joule per second.