a) initial temperature of water, tw = 5 C
final temperature = T
initial mass of water, m = 1 kg
initaial temperature of ice = -5C = ti
initial mass of ice . M = 0.035 kg
hence from heat conservation'
energy lost by ice energy gained by water
MLf * Mc(ti) + MC(T - ti) = mC(tw - T)
here, Lf is latent heat of fusion of water, c is heat capacity of ice, C is heat capacity of water
0.035(333550 + 2108*5 + 4187(T + 5)) = 1*4187(5 - T)
1. T = 1.8827 C
2. Final phase = liquid
Get Answers For Free
Most questions answered within 1 hours.