Question

Calculate No(E), the density of occupied states for a metal with a Fermi energy of 6.10 eV and at a temperature of 995 K for an energy E of (a) 4.10 eV, (b) 5.85 eV, (c) 6.10 eV, (d) 6.35 eV, and (e) 8.10 eV.

Answer 1

Density of occupied state for a metal is

Now for T= 995K and Ef= 6.1 eV,    k=8.61 * 10^{-5}eV/K

a) E=4.1

so putting values we get

so we get nearly equal to =1

b) for E= 5.85 eV

c) for E=Ef[= 6,1eV

so

d) E=6.35eV

e) E= 8.1eV

which is nearly equal to 0

so for these value we observed step function nature fermi function