If a single-mirror optical telescope could resolve an Earth-size planet 5 light years away. Calculate the minimum size of the mirror.
Okay, Here we need to assume some wavelength in the visible range.
I am assuming a wavelength of 500 nm
Therefore,
To resolve the given planet, the angular resolution
= 2R / d
where R is radius of earth as we are told that planet is having size of earth
so,
= 2 * 6370 * 1000 / 5 * 9.461e15
= 2.693e-10 rad
so,
we know as per Rayleigh
= 1.22 / D
2.693e-10 = 1.22 * 500e-9 / D
so,
D = 2265 meters
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