Question

A 0.00400-kg bullet traveling horizontally with speed 1.00 103 m/s strikes a 20.0-kg door, embedding itself 10.9 cm from the side opposite the hinges as shown in the figure below. The 1.00-m wide door is free to swing on its frictionless hinges. (a) Before it hits the door, does the bullet have angular momentum relative the door's axis of rotation? Yes No (b) If so, evaluate this angular momentum. (If not, enter zero.) kg · m2/s If not, explain why there is no angular momentum. This answer has not been graded yet. (c) Is mechanical energy of the bullet-door system constant in this collision? Answer without doing a calculation. Yes No (d) At what angular speed does the door swing open immediately after the collision? rad/s (e) Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision. KEf = J KEi = J

Answer #1

A 0.00400-kg bullet traveling horizontally with speed 1.00 103
m/s strikes a 17.7-kg door, embedding itself 10.2 cm from the side
opposite the hinges as shown in the figure below. The 1.00-m wide
door is free to swing on its frictionless hinges. (a) Before it
hits the door, does the bullet have angular momentum relative the
door's axis of rotation? Yes No (b) If so, evaluate this angular
momentum. (If not, enter zero.) kg · m2/s If not, explain why...

A 0.005 kg bullet traveling horizontally with speed 1.00 x
103 m/s strikes an 18.0-kg door, embedding itself 10.0
cm from the side opposite the hinges. The 1.00 m wide door is free
to swing on its frictionless hinges.
A) What is the bullet’s initial angular momentum relative to the
door’s axis of rotation?
B)At what angular speed does the door swing open immediately
after the collision?

A 10 g bullet traveling at 370 m/sm/s strikes a 14 kg ,
1.2-mm-wide door at the edge opposite the hinge. The bullet embeds
itself in the door, causing the door to swing open.
What is the angular velocity of the door just after impact?
Express your answer to two significant figures and include the
appropriate units.

A 0.0200 kg bullet moving horizontally at 400 m/s embeds itself
into an initially stationary 0.500 kg block.
(a) What is their velocity just after the collision? m/s
(b) The bullet-embedded block slides 8.0 m on a horizontal
surface with a 0.30 kinetic coefficient of friction. Now what is
its velocity? m/s
(c) The bullet-embedded block now strikes and sticks to a
stationary 2.00 kg block. How far does this combination travel
before stopping? m

1. A railroad car of mass 2.40E+4 kg moving with a speed of 3.10
m/s collides and couples with two other coupled railroad cars each
of the same mass that are already moving in the same direction at a
speed of 1.00 m/s.
a. What is the speed (in m/s) of the three coupled cars after
the collision?
b.How much kinetic energy (in J) is lost in the collision?
2.A ring (2 kg, r = 2 m) rotates in a...

The figure shows an overhead view of a 1.80 kg plastic rod of
length 1.20 m on a table. One end of the rod is attached to the
table, and the rod is free to pivot about this point without
friction. A disk of mass 33.0 g slides toward the opposite end of
the rod with an initial velocity of 39.5 m/s. The disk strikes the
rod and sticks to it. After the collision, the rod rotates about
the pivot...

A 10.0 kg uniform, a disk-shaped wooden door (radius 0.500 m)
hangs vertically and can rotate freely about an axis that passes
through its rim. A 0.020-kg bullet shot horizontally with a speed
of 375 m/s, hits, and embeds itself in the door at a point
diametrically opposed to the pivot point of the door.
What is the angular speed of the door after the collision? (You
can neglect the mass of the bullet after the collision.)
After the collision,...

A bullet of mass ma= 0.01 kg moving with an initial
speed of va= 200 m/s embeds itself in a wooden block
with mass mb= 0.99 kg moving in the same direction with
an initial speed vb= 2.6 m/s. What is the speed of the
bullet-embedded block after the collision? What is the total
kinetic energy of the bullet and block system before and after the
collision?

The driver of a 800.0 kg car decides to double the speed from
20.3 m/s to 40.6 m/s. What effect would this have on the amount of
work required to stop the car, that is, on the kinetic energy of
the car?
KEi=___________×105 J
KEf= __________× 105 J

A 2.50 g bullet, traveling at a speed of 460 m/s, strikes the
wooden block of a ballistic pendulum, such as that in the figure
below. The block has a mass of 270 g.
(a) Find the speed of the bullet/block combination immediately
after the collision.
(b) How high does the combination rise above its initial
position?

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