The corret answer is 1) 12.65 N/c i
Work done = change in kinetic energy of the electron
So here, work done by the electic field = 0- 1/2 mv²
Where 0 is the final kinetic energy
m is the mass of electron = 9.1*10-31Kg
V is the velocity of electron = 2*106 m/s
So work done = 1/2 * 9.1*10-31*(2*106)²
W = 1.82*10-18 J
Here work done = force * displacement
And force = Eq
Where E is the electic field and q is the charge of electron= 1.6*10-19C
Displacement = 90 cm = 0.9 m
So subtituting the values,
1.82*10-18 = E * 1.6*10-19 * 0.9
E = 1.82*10-18/(1.6*10-19*0.9)
E = 12.64 N/C
OR approximately elecric field = 12.65 N/
Since the electron is negative charged and elecric field travel from positive to negative charges, the direction of elecric field is towards + x axis (i).
So elecric field = 12.65i
(Please upvote if helpful)
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