Two masses, mass A (1.4 kg) and B (3.7 kg) are hung on either side of a pulley. The masses each have an initial speed of 1 m/s, with mass B moving up. How high, in m, does mass B move after being released at this initial speed?
For bloc A -
T- 1.4 g = 1.4 a ........ (i) where T= tension , a= acceleration
For block B -
3.7 g - T = 3.7 a ................(ii)
add equation i & ii
2.3 g = 5.1 a
2.3 *9.8 = 5.1 a
a = 22.54/5.1
a = 4.42 m/s2
By using formula Vf2 = Vi2 + 2ah where final velocity Vf = 0
0 = 12 - 2*4.42h inetial velocity Vi = 1m/s
8.84 h = 1 accelaretion a= -4.42 m/s2
h= 1/8.84 hight h =?
h = 0.113 m ...............Ans
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