Question

1) A spring with elongation constant n was cut in half. What is the elongation constant for the half spring?

A) 2n

B) 3/2n

C) N

D) n/2

2) How does the effective mass of the spring influence its behavior?

A) It increases the elongation constant.

B) It decreased the elongation constant.

C) It increases the periodic time.

D) It decreased the periodic time.

3) What is the relation between the total mass and effective mass of a spring?

A) The total mass is always larger.

B) The effective mass is always larger.

C) They are always equal.

D) There is no relation.

4) A spring of uniform density and total mass M. What do you expect its effective mass to be?

A) 2M

B) M

C) M/2

D) M/3

Answer 1

1)Option (c) N is correct. Elongation constant does not depend up on length. Thus, when a spring has cut into a half then it's elongation constant would not change.

2) Elongation constant does not depend upon mass. Time period is directly propotional to mass and thus, it will increase.

3) Total mass is the sum of mass and mass of the spring. Effective mass is the mass of spring. Thus, totall mass is always larger.

Option (A) is correct.

4) Effective mass of a spring with uniform desnity = M/3. It does not depend upon the direction of the system.

Option (D) M/3 is correct.