Question

A simple pendulum has a mass of 0.150 kg and a length of 4.00 m. It...

A simple pendulum has a mass of 0.150 kg and a length of 4.00 m. It is displaced through an angle of 7.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.)

(a) What is the maximum speed of the bob?
m/s

(b) What is the maximum angular acceleration of the bob?
rad/s2

(c) What is the maximum restoring force of the bob?
N

(d) Solve parts below using other analysis models. (Hint: you may need to use separate analysis models for each part.)

1. maximum speed

m/s

2. maximum angular acceleration rad/s2
3. maximum restoring force N


(e) Compare the answers.

Homework Answers

Answer #1

mass, m = 0.15 kg

length of the pendulum, L = 4 m

angle, ? = 7o

sin 7o = A / L

? amplitude, A = L*sin 7o

                        = 0.49 m

time period of the simple pendulum, T = 2? ?[ L / g] = 2? ?[ 4 / 9.81] = 4.012 s

( a) maximum speed = A ?

where ? =angular frequency = 2? / T = 2? / 4.012 = 1.6 rad/s

maximum speed = A ? = 0.49*1.6 = 0.77 m/s

( b ) maximum angular acceleration = A ?2 = 0.49*1.62 = 1.23 rad/s2

( c ) maximum restoring force F = mA ?2 = 0.15*1.23 = 0.18 N

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A simple pendulum has a mass of 0.550 kg and a length of 4.00 m. It...
A simple pendulum has a mass of 0.550 kg and a length of 4.00 m. It is displaced through an angle of 10.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.) (a) What is the maximum speed of the bob? our response differs from the correct answer by more than 100%. m/s (b) What is the maximum angular acceleration of the bob? rad/s2 (c)...
A simple pendulum has a mass of 0.450 kg and a length of 3.00 m. It...
A simple pendulum has a mass of 0.450 kg and a length of 3.00 m. It is displaced through an angle of 6.0° and then released. Solve this problem by using the simple harmonic motion model for the motion of the pendulum. (a) What is the maximum speed? ___m/s (b) What is the maximum angular acceleration? ___rad/s2 (c) What is the maximum restoring force? ___N
The length of a simple pendulum is 0.85 m and the mass of the particle (the...
The length of a simple pendulum is 0.85 m and the mass of the particle (the "bob") at the end of the cable is 0.26 kg. The pendulum is pulled away from its equilibrium position by an angle of 7.75° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? rad/s (b) Using the position of the bob at its lowest...
A simple pendulum with mass m = 2 kg and length L = 2.67 m hangs...
A simple pendulum with mass m = 2 kg and length L = 2.67 m hangs from the ceiling. It is pulled back to an small angle of θ = 11° from the vertical and released at t = 0. 1)What is the period of oscillation? s   2)What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? N   3)What is the maximum speed of the pendulum? m/s   4)What is the angular displacement at...
A simple pendulum with a length of 2.73 m and a mass of 6.54 kg is...
A simple pendulum with a length of 2.73 m and a mass of 6.54 kg is given an initial speed of 1.36 m/s at its equilibrium position. (a) Assuming it undergoes simple harmonic motion, determine its period. s (b) Determine its total energy. J (c) Determine its maximum angular displacement. (For large v, and/or small l, the small angle approximation may not be good enough here.) °
A toy of mass 0.150 kg is undergoing simple harmonic motion (SHM) on the end of...
A toy of mass 0.150 kg is undergoing simple harmonic motion (SHM) on the end of a horizontal spring with force constant 300 N/m . When the object is a distance 1.25×10?2 m from its equilibrium position, it is observed to have a speed of 0.305 m/s . a) What is the total energy of the object at any point of its motion? b) What is the amplitude of the motion? c) What is the maximum speed attained by the...
1. A(n) _____ is an example of Simple Harmonic Motion. ticking wrist-watch oscillating mass on a...
1. A(n) _____ is an example of Simple Harmonic Motion. ticking wrist-watch oscillating mass on a spring beating heart All of the above 2. _____ is a measure of the maximum displacement for oscillatory motion. Amplitude Frequency Equilibrium All of the above 3.The restoring force is calculated using the equation _____. F = kx F = -kx F = kx2 None of the above 4. The restoring force for a pendulum is proportional to the mass and inversely proportional to...
A simple pendulum is constructed from a string of negligible mass. A mass (bob) 0.91kg that...
A simple pendulum is constructed from a string of negligible mass. A mass (bob) 0.91kg that is essentially a point mass. The string length is 0.65m. The pendulum is started by being released from rest with an angle (respect to the vertical) of 5.87 degrees. Use g=9.81 m/s^2. a) the maximum amplitude (in degrees) of this motion b)Angular frequency (in rad/s) of this motion c) Period (in s) of this motion.
A simple pendulum has a length of 85 cm and a bob of mass 1.1 kg....
A simple pendulum has a length of 85 cm and a bob of mass 1.1 kg. When the string is at 28 degrees to the vertical. the bob has a speed of 2.5 m/s. a) What is the maximum speed of the bob? b) What is the maximum angle to the vertical? degrees
A 6.5-kg mass is attached to an ideal 750-N/m spring. If the system undergoes simple harmonic...
A 6.5-kg mass is attached to an ideal 750-N/m spring. If the system undergoes simple harmonic motion, what are the frequency, angular frequency, and period of the motion? The frequency, f = The angular frequency, ω = The period, T =   If the total mechanical energy of the system is 72 J, what are the amplitude, maximum speed and maximum acceleration of the motion? The amplitude, A =   The maximum speed, vmax = The maximum acceleration, amax =
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT